Triangular prism volume, cylinders, cones and other 3D shapes

1. Area of the triangle.
   $$\tfrac{1}{2} \times 6 \times 4 = 12\text{ cm}^2$$
2. Multiply by the length.
   $$12 \times 10 = 120\text{ cm}^3$$

Resposta: $120\text{ cm}^3$

✓ Verificado pelo motor matemático do Sumzo

1. Two triangles.
   $$2 \times \tfrac{1}{2} \times 3 \times 4 = 12$$
2. Three rectangles: the perimeter of the triangle times the length.
   $$(3 + 4 + 5) \times 10 = 120$$
3. Add.
   $$12 + 120 = 132\text{ cm}^2$$

Resposta: $132\text{ cm}^2$

✓ Verificado pelo motor matemático do Sumzo

1. The cross-section is a circle, area $\pi r^2$.
   $$V = \pi r^2 h = \pi \times 4 \times 7$$
2. Simplify.
   $$28\pi \approx 87.96\text{ cm}^3$$

Resposta: $28\pi \approx 87.96\text{ cm}^3$

✓ Verificado pelo motor matemático do Sumzo

1. A cone is one third of the cylinder with the same base and height.
   $$V = \tfrac{1}{3}\pi r^2 h = \tfrac{1}{3}\pi \times 9 \times 4$$
2. Simplify.
   $$12\pi \approx 37.70\text{ cm}^3$$

Resposta: $12\pi \approx 37.70\text{ cm}^3$

✓ Verificado pelo motor matemático do Sumzo