Abonnementen

Rekenmachine meetkundige rij (n-de term en som)

Deze rekenmachine berekent de n-de term en de som van de eerste n termen van een rij waarin elke term de vorige keer hetzelfde getal is. Als de reden tussen −1 en 1 ligt, geeft hij ook de oneindige som.

Resultaat

Vul waarden in en tik op Berekenen om het resultaat te zien.

Formule

an=a1rn−1a_n = a_1 r^{n-1}

Multiply the first term by the ratio n − 1 times.

Sn=a1(1−rn)1−r,r≠1S_n = \frac{a_1(1 - r^n)}{1 - r}, \quad r \neq 1

The sum of the first n terms.

S∞=a11−r,∣r∣<1S_\infty = \frac{a_1}{1 - r}, \quad |r| < 1

The sum to infinity exists only when the terms shrink towards 0.

Zo gebruik je deze rekenmachine

  1. Enter the first term and the common ratio (divide any term by the one before it).
  2. Enter n, the term you want (and how many terms to add).
  3. Press Calculate to see the nth term, the sum, the first terms and the infinite sum if it exists.

Uitgewerkte voorbeelden

2, 6, 18, … : the 5th term and the sum of 5 terms

a₅ = 2 × 3⁴ = 162.

S₅ = 2(1 − 3⁵)/(1 − 3) = 2 × (−242)/(−2) = 242.

r = 3 > 1, so there is no sum to infinity.

8, 4, 2, … : halving each time

a₄ = 8 × (1/2)³ = 1.

S₄ = 8 + 4 + 2 + 1 = 15.

Sum to infinity: 8/(1 − 1/2) = 16.

Alternating signs: 5, −10, 20, …

a₆ = 5 × (−2)⁵ = −160.

S₆ = 5(1 − 64)/(1 + 2) = −105.

Veelgemaakte fouten

  • Using rⁿ instead of rⁿ⁻¹ for the nth term.
  • Finding r by subtracting terms (that is the arithmetic difference); divide instead.
  • Using the sum to infinity when |r| ≥ 1: the sum grows without limit.

Veelgestelde vragen

How do you find the common ratio?

Divide a term by the one before it: 6 ÷ 2 = 3. The ratio is the same for every pair.

When does a geometric series have a sum to infinity?

Only when −1 < r < 1, so the terms get smaller and smaller. Then S∞ = a₁/(1 − r).

What is the difference between arithmetic and geometric sequences?

An arithmetic sequence adds the same number each time (3, 7, 11); a geometric sequence multiplies by the same number (2, 6, 18).