Calculatrice du vecteur tangent unitaire
Cette calculatrice trouve T(t) = r′(t)/|r′(t)| pour une courbe r(t) = ⟨x(t), y(t), z(t)⟩ dont les composantes sont des polynômes en t. Elle dérive chaque composante, calcule la norme de r′(t) et donne T exactement pour la valeur de t choisie — par exemple ⟨1/3, 2/3, 2/3⟩ — avec des décimales quand des racines apparaissent.
Résultat
Saisissez les valeurs et appuyez sur Calculer pour voir le résultat.
Formule
Divide the velocity vector by its length so the result has length 1.
The length (speed) of r′(t).
Comment utiliser cette calculatrice
- Choose a 2D or 3D curve.
- Type each component as a polynomial in t, such as t, t^2 and 2t^3/3.
- Enter the value of t and press Calculate: you get T at that point, the speed |r′(t)|, and the general formula for T(t).
Exemples corrigés
Easy: a 2D curve at t = 0
r′(t) = ⟨3, 4 − 2t⟩, so r′(0) = ⟨3, 4⟩.
|r′(0)| = √(9 + 16) = 5.
T(0) = ⟨3, 4⟩/5 = ⟨3/5, 4/5⟩.
Medium: a 3D curve with a whole-number speed
r′(t) = ⟨1, 2t, 2t²⟩, so r′(1) = ⟨1, 2, 2⟩.
|r′(1)| = √(1 + 4 + 4) = 3.
T(1) = ⟨1/3, 2/3, 2/3⟩.
Hard: a surd in the length
r′(t) = ⟨2t, 3t²⟩, so r′(1) = ⟨2, 3⟩.
|r′(1)| = √(4 + 9) = √13.
T(1) = ⟨2/√13, 3/√13⟩ = ⟨(2√13)/13, (3√13)/13⟩ ≈ ⟨0.5547, 0.8321⟩.
Erreurs fréquentes
- Dividing r(t) by its length instead of r′(t): the tangent comes from the derivative.
- Forgetting to square each component before adding under the square root.
- Trying to find T where r′(t) = 0: the curve has no defined direction there.
- Leaving out the z-component of a 3D curve when finding the length.
Questions fréquentes
What is the unit tangent vector?
T(t) is the direction of motion along a curve r(t), scaled to length 1: T(t) = r′(t)/|r′(t)|. It points the way the curve is heading at each t.
How do you find the unit tangent vector at a point?
Differentiate each component to get r′(t), substitute the value of t, find the length of that vector, and divide each component by the length.
Can I enter sin t or e^t?
Not yet — each component must be a polynomial in t, such as 3t^2 - t + 1. The answer is then exact.
How is the answer checked?
The calculator squares the components of T and adds them: the total must be exactly 1.